+ 'More generally, let $\mathcal{C}$ be a thin finitary algebraic category. Let $F : \mathbf{Set} \to \mathcal{C}$ denote the free algebra functor. Every object $A \in \mathcal{C}$ admits a regular epimorphism $F(X) \to A$ for some set $X$. But since $\mathcal{C}$ is left cancellative, every regular epimorphism must be an isomorphism. Also, $F(X)$ is a coproduct of copies of $F(1)$, which means it is either the initial object $0$ or $F(1)$ itself (since $\mathcal{C}$ is thin). This shows that $\mathcal{C}$ must have at most $2$ objects up to isomorphism. In fact, either $\mathcal{C}$ is trivial or equivalent to the <a href="/category/walking_morphism">interval category</a> $\{0 \to 1\}$ (which <i>is</i> finitary algebraic).'
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