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main.go
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75 lines (68 loc) · 2.4 KB
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// Source: https://leetcode.com/problems/number-of-laser-beams-in-a-bank
// Title: Find Players With Zero or One Losses
// Difficulty: Medium
// Author: Mu Yang <http://muyang.pro>
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// You are given an integer array matches where matches[i] = [winner_i, loser_i] indicates that the player winner_i defeated player loser_i in a match.
//
// Return a list answer of size 2 where:
// * answer[0] is a list of all players that have not lost any matches.
// * answer[1] is a list of all players that have lost exactly one match.
//
// The values in the two lists should be returned in increasing order.
//
// Note:
// * You should only consider the players that have played at least one match.
// * The testcases will be generated such that no two matches will have the same outcome.
//
// Example 1:
//
// Input: matches = [[1,3],[2,3],[3,6],[5,6],[5,7],[4,5],[4,8],[4,9],[10,4],[10,9]]
// Output: [[1,2,10],[4,5,7,8]]
// Explanation:
// Players 1, 2, and 10 have not lost any matches.
// Players 4, 5, 7, and 8 each have lost one match.
// Players 3, 6, and 9 each have lost two matches.
// Thus, answer[0] = [1,2,10] and answer[1] = [4,5,7,8].
//
// Example 2:
//
// Input: matches = [[2,3],[1,3],[5,4],[6,4]]
// Output: [[1,2,5,6],[]]
// Explanation:
// Players 1, 2, 5, and 6 have not lost any matches.
// Players 3 and 4 each have lost two matches.
// Thus, answer[0] = [1,2,5,6] and answer[1] = [].
//
// Constraints:
//
// 1 <= matches.length <= 10^5
// matches[i].length == 2
// 1 <= winner_i, loser_i <= 10^5
// winner_i != loser_i
// All matches[i] are unique.
//
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
package main
func findWinners(matches [][]int) [][]int {
n := int(1e5 + 1)
winCount := make([]int, n)
loseCount := make([]int, n)
for _, match := range matches {
winCount[match[0]]++
loseCount[match[1]]++
}
winners := make([]int, 0, len(winCount))
for player, count := range winCount {
if count > 0 && loseCount[player] == 0 {
winners = append(winners, player)
}
}
losers := make([]int, 0, len(loseCount))
for player, count := range loseCount {
if count == 1 {
losers = append(losers, player)
}
}
return [][]int{winners, losers}
}