int_triangle.cpp

#include <iostream>
#include <cmath> 
using namespace std;

int main(int argc, char* argv[]) { 
  cout.precision(20);
  if (argc > 1)// если передаем аргументы, то argc будет больше 1(в зависимости от кол-ва аргументов)
  {
      long long ar1 = stoi(argv[1]); // 1
      long long ar2 = stoi(argv[2]); // 1000
      long long ar3 = stoi(argv[3]); // 5000
      long double intpart;
      //long double p;
      for(long long a = ar1 ; a < ar2; a++)
      {
       if (a % 100 == 0) cout << "a=" << a << std::endl;
       for(long long b = a+1; b < ar3; b++)
       {    
        //p=a/2+b-0.5;
        for(long long c = b; c < a+b; c++)
        {
         //p+=0.5;
         if  (  modfl(sqrtl(0 - (a - b - c) * (a + b - c) * (a - b + c) * (long double)(a + b + c)), &intpart) == 0.0 
             && modfl(sqrt(2*b*b+2*c*c-a*a), &intpart) == 0.0 
             && modfl(sqrt(2*a*a+2*c*c-b*b), &intpart) == 0.0 
             && modfl(sqrt(2*a*a+2*b*b-c*c), &intpart) == 0.0)
          {
            std::cout << a << " " << b << " " << c << " ";
            std::cout << (sqrt(2*b*b+2*c*c-a*a))/2 << " " << (sqrt(2*a*a+2*c*c-b*b))/2 << " " << (sqrt(2*a*a+2*b*b-c*c))/2 << " ";
            std::cout << sqrt((a + b + c)/2*((a + b + c)/2-a)*((a + b + c)/2-b)*((a + b + c)/2-c)) << std::endl;
          }
        }
       }
      }
  }
  return 0; 
}